(i) (2x + 3/x – 1)2
(ii) (2/3 x – 3/2x – 1)2
Answer :
(i) (2x + 3/x – 1)2
It can be written as
= [2x + 3/x + (-1)]2
By further calculation
= (2x)2 + (3/x)2 + (-1)2 + 2 ×2x × 3/x + 2 × 3/x × (-1) + 2 × (-1) × 2x
So we get
= 4x2 + 9/x2 + 1 + 12 – 6/x – 4x
= 4x2 + 9/x2 + 13 – 6/x – 4x
(ii) (2/3 x – 3/2x – 1)2
It can be written as
= [2/3 x – 3/2x – 1]2
By further calculation
= (2/3 x)2 + (-3/2x)2 + (-1)2 + 2 × 2/3 x × (-3/2x) + 2 × (-3/2x) × (-1) + 2 × (-1) × (2/3 x)
So we get
= 4/9 x2 + 9/4x2 + 1 – 2 + 3/x – 4/3 x
= 4/9 x2 + 9/4x2 – 1 – 4/3 x + 3/x
More Solutions:
- Simplify the following (a + b)2 + (a – b)2
- Simplify the following (a + 1/a)2 + (a – 1/a)2
- Simplify the following (3x – 1)2 – (3x – 2) (3x + 1)
- Simplify the following (7p + 9q) (7p – 9q)
- Simplify the following (2x – y + 3) (2x – y – 3)
- Simplify the following (x + 2/x – 3) (x – 2/x – 3)
- Simplify the following (x + 2y + 3) (x + 2y + 7)
- Simplify the following (2p + 3q) (4p2 – 6pq + 9q2)
- Simplify the following (3p – 4q) (9p2 + 12pq + 16q2)
- Simplify the following (2x + 3y + 4z)