Solve the following equations: log (2x + 3) = log 7

Solve the following equations :
(i) log (2x + 3) = log 7
(ii) log (x +1) + log (x – 1) = log 24
(iii) log (10x + 5) – log (x – 4) = 2
(iv) log105 + log10(5x+1) = log10(x + 5) + 1
(v) log (4y – 3) = log (2y + 1) – log3
(vi) log10(x + 2) + log10(x – 2) = log103 + 31og104.
(vii) log(3x + 2) + log(3x – 2) = 5 log 2.

Solution:

ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 9 Logarithms 9.2 Q22.1
ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 9 Logarithms 9.2 Q22.2

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