The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find the present age.
Solution:
Two years ago, a man’s age was three times the square of his daughter’s age. Three years hence, his age will be four times his daughter’s age. Find their present ages.
Solution:
More Solutions:
- Which of the following is a quadratic equation.
- If 1/2 is a root of the equation.
- The roots of the equation x2 – 3x – 10 = 0.
- If the equation 2x² – 5x + (k + 3) = 0 has equal roots
- If the equation 3x² – kx + 2k =0 roots.
- If the equation 2x² – 6x + p = 0 has real.
- Which of the following equations has no real roots.