In figure given alongside, ∠B = 30°, ∠C = 40° and the bisector of ∠A meets BC at D. Show
(i) BD > AD
(ii) DC > AD
(iii) AC > DC
(iv) AB > BD
Solution:
More Solutions:
- Prove that AB > CD.
- If AB > AC, show that AB > AD.
- Its sides as 4 cm, 3 cm and 7 cm?
- Which of the following is not a criterion.
- If AB = FE and BC = DE, then
- AB=AC and AD is median of ∆ABC
- If ∠ACO = ∠BDO, then ∠OAC is equal to
- If OB = 4 cm, then BD is
- In ∆ABC, AB = AC and ∠B = 50°.
- In ∆ABC, BC = AB and ∠B = 80°.