In a parallelogram ABCD, the bisector of ∠A meets DC in E and AB = 2 AD. Prove that
(i) BE bisects ∠B
(ii) ∠AEB = a right angle.
Solution:
More Solutions:
- Prove that 3 ∠POB = ∠AOP.
- Prove that EFGH is a square.
- ABCD and ABEF are parallelograms.
- Find the ratio AC : BD.
- ABCD in which ∠ BAD = 45°
- AB = 6cm, BC = 4cm, CD = 4 cm
- Construct the quadrilateral ABCD.
- Which AB = 3.3 cm, BC = 4.9 cm, CD = 5.8 cm.
- Construct a trapezium ABCD in which AD || BC
- AB = 5 cm. BC = 6.2 cm and CD = 4.8 cm.