The three angles of a quadrilateral are 75°, 90° and 75°. The fourth angle is
(a) 90°
(b) 95°
(c) 105°
(d) 120°
Solution:
Sum of 4 angles of a quadrilateral = 360° Sum of three angles = 75° + 90° + 75° = 240° Fourth angle = 360° – 240° = 120° (d)
A quadrilateral ABCD is a trapezium if
(a) AB = DC
(b) AD = BC
(c) ∠A + ∠C = 180°
(d) ∠B + ∠C = 180°
Solution:
A quadrilateral ABCD is a trapezium if ∠B + ∠C= 180°
(Sum of co-interior angles) (d)
More Solutions:
- ABCD is a rhombus such that ∠ACB = 40°.
- The diagonals AC and BD of a parallelogram ABCD.
- If the diagonals of a square ABCD
- The quadrilateral PQRS must be a
- The following statement is true for a parallelogram?
- Which the diagonals are equal and bisect each other
- How many sides does the polygon have?
- Find the number of sides.
- BC || ED and ∠B: ∠A : ∠E =3:4:5.
- Prove that AEBD is a parallelogram.