In a frequency distribution, the mid-value of a class is 10 and the width of the class is 6. The lower limit of the class is
(a) 6
(b) 7
(c) 8
(d) 12
Solution:
Mid value = 10 cm
Width = 6
Lower Limit = mid value of class – width
2
= 10 – 6
2
= 10 – 3
= 7
(b) 7 is correct
The width of each of 5 continuous classes in a frequency distribution is 5 and the lower limit of the lowest class is 10. The upper limit of the highest class is
(a) 15
(b) 25
(c) 35
(d) 40
Solution:
Upper limit of highest class is 35
As 5 width for five consecutive classes
10-15
15-20
20-25
25-30
30-35
(c) 35 is correct
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