The mean of three different natural numbers is 40. If lowest is 19, what could be highest possible number of remaining two numbers?
(a) 40
(b) 71
(c) 81
(d) 100
Solution:
The mode of the data:
3, 5, 1, 2, 0, 2, 3, 5, 0, 2, 1, 6 is
(a) 6
(b) 3
(c) 2
(d) 1
Solution:
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