The number of matchsticks in 40 boxes on counting was found as given below:
44, 41, 42, 43, 47, 50, 51, 49, 43, 42, 40, 42, 44, 45, 49, 42, 46, 49, 45, 49, 45, 47, 48, 43, 43, 44, 48, 43, 46, 50, 43, 52, 46, 49, 52, 51, 47, 43, 43, 45.
Taking classes 40-42, 42-44 ….., construct the frequency distribution table for the above data. Also draw a combined histogram and frequency polygon to represent the distribution.
Solution:
Class Intervals | Tally Marks | Frequency |
40-42 | II | 2 |
42-44 | 12 | |
44-46 | 7 | |
46-48 | 6 | |
48-50 | 7 | |
50-52 | IIII | 4 |
52-54 | II | 2 |
Total | 40 |
Take class on x-axis and frequency on y-axis :
More Solutions:
- The class marks of a frequency distribution are given:
- A grouped frequency distribution table with class intervals:
- If the mean of x1, x, is 7.5, and the mean of x1, X2, x3 is;
- The mean of 100 observations is 50.
- For drawing a frequency polygon of a continuous frequency distribution.
- The mean and the median of the following set of numbers:
- Find the mean and the median of all the (positive) factors of 48.
- Find the mean weight of the remaining students.
- What is the new mean age?