The point which lies on the perpendicular bisector of the line segment joining the points A (-2, -5) and B (2, 5) is
(a) (0, 0)
(b) (0, 2)
(c) (2, 0)
(d) (-2, 0)
Solution:
The coordinates of the point which is equidistant from the three vertices of ∆AOB (shown in the given figure) are
(a) (x, y)
(b) (y, x)
(c) 
(d) 
Solution:
More Solutions:
- ABCD is a parallelogram whose vertices A and B.
- In the adjoining figure, P (3, 1) is the point on the line segment.
- Given, O, (0, 0), P(1, 2), S(-3, 0) P divides OQ in the ratio of 2 : 3.
- Find the slope of a line whose inclination is
- Find the equation of a straight line parallel to y-axis.
- Find the slope and y-intercept of the following lines: