The probability of getting atleast one head is :

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If two coins are tossed simultaneously, then the probability of getting atleast one head is
(a) \\ \frac { 1 }{ 4 }
(b) \\ \frac { 1 }{ 2 }
(c) \\ \frac { 3 }{ 4 }
(d) 1

Solution:

Two coins are tossed
Total outcomes = 2 × 2 = 4
Probability of getting atleast one head (HT,TH,H,H) = \\ \frac { 3 }{ 4 } (c)

Lakshmi tosses two coins simultaneously. The probability that she gets almost one head
(a) 1
(b) \\ \frac { 3 }{ 4 }
(c) \\ \frac { 1 }{ 2 }
(d) \\ \frac { 1 }{ 7 }

Solution:

Two coins are tossed
Total number of outcomes = 2 × 2 = 4
Probability of getting atleast one head = (HT, TH, RH = 3) = \\ \frac { 3 }{ 4 } (b)

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