The value of 3 tan2 26° – 3 cosec2 64° is

The value of 3 tan2 26° – 3 cosec2 64° is
(a) 0
(b) 3
(c) – 3
(d) – 1

Solution:

3 tan2 26° – 3 cosec2 64°
= 3 tan2 26° – 3 cosec (90° – 26°)
= 3 tan2 26° – 3 sec2 26°
ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 18 Trigonometric Identities MCQS Q11.1

The value of \frac { sin({ 90 }^{ O }-\theta )sin\theta }{ tan\theta } -1 is
(a) – cot θ
(b) – sin2 θ
(c) – cos2 θ
(d) – cosec2 θ

Solution:

\frac { sin({ 90 }^{ O }-\theta )sin\theta }{ tan\theta } -1
ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 18 Trigonometric Identities MCQS Q12.1

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