The value of a machine worth ₹ 500000 is depreciating at the rate of 10% every year. In how many years will its value be reduced to ₹ 364500?
Solution:
It is given that
Present value = ₹ 500000
Reduced value = ₹ 364500
Rate of depreciation = 10% p.a.
Consider n years as the period
We know that
A/P = (1 – r/100)n
Substituting the values
364500/500000 = (1 – 10/100)n
By further calculation
(9/10)n = 729/1000 = (9/10)3
So we get
n = 3
Therefore, the period in which its value be reduced to ₹ 364500 is 3 years.
More Solutions:
- If a man invests ₹12000 for two years.
- The compound interest on ₹5000 at 20%.
- The present population of a city is 12,00,000.
- ₹ 10000 was lent for one year at 10% per annum.
- A man invests ₹ 3072 for two years at compound interest.
- Also find the compound interest.
- Two equal sums were lent at 5% and 6% per annum.
- The compound interest on a sum of money for 2 years.
- The simple and compound interest for 3 years.