The value of k if on dividing 2×3 + 3×2 – kx + 5 by x – 2

Using remainder theorem, find the value of k if on dividing 2x³ + 3x² – kx + 5 by x – 2, leaves a remainder 7. (2016)

Solution:

Using remainder theorem, find the value of a, if the division of x³ + 5x² – ax + 6 by (x – 1) leaves the remainder 2a.

Solution:

More Solutions:

• If (x + 2) and (x – 3) are factors of x3 + ax + b.
• If (x – 2) is a factor of the expression 2×3 + ax2 + bx – 14
• If ax3 + 3×2 + bx – 3 has a factor (2x + 3) and leaves remainder – 3
• When x3 – 3×2 + 5x – 7 is divided by x – 2.
• If on dividing 4×2 – 3kx + 5 by x + 2.