Then find the value of x.

If (sec2 59° – cot2 31°) – sin 90° + 3tan2 56° tan2 34° = , then find the value of x.

Solution:

Given
(sec2 59° – cot2 31°) – sin 90° + 3tan2 56° tan2 34° =

(i)
(ii)

Solution:

(i)
L.H.S =

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