There are four numbers such that the first three of them form an A.P.

There are four numbers such that the first three of them form an A.P. and the last three form a GP. The sum of the first and third number is 2 and that of the second and fourth is 26. What are these numbers?

Solution:

(i) If a, b, c are in A.P. as well in G.P., prove that a = b = c.
(ii) If a, b, and c are in A.P as well as in G.P., then find the value of a^b-c + b^c-a + c^a-b

Solution:

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