Two chords AB, CD of a circle intersect internally at a point P. If
(i) AP = cm, PB = 4 cm and PD = 3 cm, find PC.
(ii) AB = 12 cm, AP = 2 cm, PC = 5 cm, find PD.
(iii) AP = 5 cm, PB = 6 cm and CD = 13 cm, find CP.
Solution:
More Solutions:
- In the figure given below, O is the centre of the circle.
- Given below, PQ is a diameter. Chord SR is parallel to PQ.
- AB is a diameter of the circle. If ∠ADC = 120°, find ∠CAB.
- ABCD is a quadrilateral inscribed in a circle with centre O.
- PQRS is a cyclic quadrilateral in which PQ = QR and RS is produced to T.
- Given below, O is the centre of the circle.