#### The area of a square whose vertices are A (0, -2), B (3, 1), C (0, 4) and D (-3, 1) is

(a) 18 sq. units

(b) 15 sq. units

(c) 18−−√ sq. units

(d) 15−−√ sq. units

**Solution:**

**More Solutions:**

- Three vertices of a rectangle are A (2, -1), B (2, 7), and C (4, 7).
- What is the area of the parallelogram?
- Also find slope and y-intercept of these lines.
- Draw the graph of the equation 3x – 4y = 12.
- The simultaneous equations: 2x – 3y = 7; x + 6y = 11.
- System of equations graphically: x – 2y – 4 = 0, 2x + .y – 3 = 0.
- Using a scale of l cm to 1 unit for both the axes.
- The lines : 8y – 3x + 7 = 0, 2x-y + 4 = 0 and 5x + 4y = 29.
- Find the area of the triangle formed by these lines.
- Find the abscissa of the other end.