what is the probability that the coin.

A piggy bank contains a hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins, and ten Rs 5 coins. It is equally likely that one of the coins will fall down when the bank is turned upside down, what is the probability that the coin
(i) will be a 50 p coin?
(ii) will not be Rs 5 coin?

Solution:

In a piggy bank, there are
100, 50 p coin
50, Rs 1 coin
20, Rs 2 coin
10, Rs 5 coin
Total coins = 100 + 50 + 20 + 10 = 180
One coin is drawn at random Probability of
(i) 50 p coins = \\ \frac { 100 }{ 180 }
= \\ \frac { 5 }{ 9 }
(ii) Will not be Rs 5 coins
= 100 + 50 + 20 = 170
Probability = \\ \frac { 170 }{ 180 } = \\ \frac { 17 }{ 18 }

A carton consists of 100 shirts of which 88 are good, 8 have minor defects and 4 have major defects. Peter, a trader, will only accept the shirts which are good, but Salim, another trader, will only reject the shirts which have major defects. One shirts is drawn at random from the carton. What is the probability that
(i) it is acceptable to Peter?
(ii) it is acceptable to Salim?

Solution:

In a carton, there the 100 shirts.
Among these number of shirts which are good = 88
number of shirts which have minor defect = 8
number of shirt which have major defect = 4
Total number of shirts = 88 + 8 + 4 = 100
Peter accepts only good shirts i.e. 88
Salim rejects only shirts which have major defect i.e. 4
(i) Probability of good shirts which are acceptable to Peter
P(E) = \frac { Number\quad of\quad favourable\quad outcome }{ Number\quad of\quad possible\quad outcome }
= \\ \frac { 88 }{ 100 }
= \\ \frac { 22 }{ 25 }
(ii) Probability of shirts acceptable to Salim
P(E) = \frac { Number\quad of\quad favourable\quad outcome }{ Number\quad of\quad possible\quad outcome }
= \\ \frac { 88+8 }{ 100 }
= \\ \frac { 96 }{ 100 }
= \\ \frac { 24 }{ 25 }

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