What must be subtracted from 3a^2 – 5ab – 2b^2 – 3 to get 5a^2 – 7ab – 3b^2 + 3a

What must be subtracted from 3a² – 5ab – 2b² – 3 to get 5a² – 7ab – 3b² + 3a ?

Solution:

The perimeter of a triangle is 7p² – 5p + 11 and two of its sides are p² + 2p – 1 and 3p² – 6p + 3. Find the third side of the triangle.

Solution:

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