When the sum of a 2-digit number ab and number obtained by reversing the digits is divided by (a + b), the quotient is
(a) a – b
(b) 9
(c) 11
(d) None of these
Solution:
When the sum of a 3-digit number abc and numbers obtained by changing the order of the digits cyclically is divided by 111, then the quotient is
(a) 37
(b) a – b + c
(c) a + b + c
(d) 3
Solution:
If A + A + A = BI, where A and B are different digits, then
(a) A = 1, B = 5
(b) A = 5, B = 2
(c) A = 5, B = 1
(d) A = 7, B = 2
Solution:
More Solutions:
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