**Construct a quadrilateral ABCD in which AB = 3.3 cm, BC = 4.9 cm, CD = 5.8 cm, DA = 4 cm and BD = 5.3 cm.**

**Solution:**

**More Solutions:**

- Prove that 3(AB² + BC² + CA²) = 4(AD² + BE² + CF²).
- Prove that AB² + CD² = AD² + BC².
- Prove that 2 AC² – BC2 = AB² + AD² + DC².
- Prove that : DC² – BD² = 2AB. AD.
- Prove that AD² = AC² + BD.CD.
- Calculate the length of PR and QR.
- If AB = 6√3 cm, BC = 6 cm and AC = 12 cm
- The length of its diagonal is
- The length of the side of the rhombus is
- The length of the other diagonals is