A wire when bent in the form of an equilateral triangle encloses an area of 36√3 cm2. Find the area enclosed by the same wire when bent to form:
(i) a square, and
(ii) a rectangle whose length is 2 cm more than its width.
Solution:
More Solutions:
- AD is a diameter of a circle and AB.
- If AB = 12 cm, BC = 16 cm and AB.
- O is the centre of the circle.
- Find the lengths of :
- If QR = 12 cm, calculate PQ.
- Find its distance from the centre of the circle.
- Calculate the distance CD.
- Prove that NOMP is a square.
- Prove that AD bisects ∠BAC and ∠BDC.
- Find the area of a triangle.