To practice for exams or any other competitive tests on the concept of finding Percent, you can find here different types of questions with solutions. The Percent means per hundred which are used to share the amount in terms of hundred. And the percentage can be represented with the symbol %. This is also used to define a portion of a fraction of a whole. In the below, you can see some of the examples of finding percent. Practice using the Finding Percentage Worksheets and clear the exam with better grades.
How to Find Percent?
To find the percent, we will multiply the given number, fraction, or a decimal by 100 and then we will add the percent symbol %. So, for example, if we consider two variables X and Y to calculate the percent of X which represents Y and we will divide Y with X, then we will multiply the result by 100. Let’s solve some of the examples below.
1. Find the percent of the following:
(i) 2.6 liters is 130 ml.
(ii) 300 ml is 1500 ml.
(iii) 6 kg is 300 g
Solution:
(i) 2.6 liters is 130 ml.
Given 130 ml of 2.6 liters,
as we know 1 liter= 1000 ml, so we will convert liter to ml,
2.6 liters= 2.6×1000
= 2,600 ml,
so, to find the percent
130/2600 × 100=
on solving we will get the result as
=5%.
(ii) 300 ml is 1500 ml.
Given 1500 ml of 300 ml, which means
300/1500 × 100=
on solving we will get the result as
= 20%.
(iii) 6 kg is 300 g
Given 300g of 6 kg,
as we know 1 kg= 1000 g, so we will convert kg to g,
6kg= 6×1000 = 6000 g
300/6000 × 100=
on solving we will get the result as
= 5%.
2. Solve the following:
(i) 60 cm as a percent of 5 m.
(ii) 20 mins as a percent of 2 hours.
(iii) 1.25 mm as a percent of 2.5 cm
Solution:
(i) 60 cm as a percent of 5 m.
Given 60 cm of 5m,
as 1m= 100 cm, so first we will convert meters to centimeters
5m= 500 cm,
60/500 × 100 =
on solving we will get the result as
= 12%.
(ii) 20 mins as a percent of 2 hours.
Given 20 mins of 1 hour,
as 1 hour = 60 minutes, so we will convert hour to minutes,
2 hour= 120 minutes,
2/120 × 100=
on solving we will get the result as
16.67%.
(iii) 1.25 mm as a percent of 2.5 cm
Given 1.25mm of 2.5 cm
as 1 cm= 10 mm, so we will convert cm to mm
2.5 cm = 25 mm,
1.25/25 × 100=
on solving we will get
5%.
3. Fill up the below empty space:
(i) 5 is _________ % of 25.
(ii) 70 cm is _________ % of 140 cm.
(iii) 15 liters is __________ % of 300 liters.
Solution:
(i) 5 is _________ % of 25.
Given 5 percent of 25, which means
5/25 × 100
on solving, we will get the result as
20%.
So, 5 is 20% of 25.
(ii) 70 cm is _________ % of 140 cm.
Given 70 cm of 140 cm, which means
70/140 × 100
on solving, we will get the result as
5%.
So, 70 cm is 5% of 140 cm.
(iii) 15 liters is __________ % of 300 liters.
Given 15 liters of 300 liters, which means
15/300 × 100
on solving, we will get the result as
5%
So, 15 liters is 5 % of 300 liters.
4. The water tanks contain 160 liters of water. By the leakage of the tank, 20 liters of water is lost. What percent of water is lost?
Solution:
As the tank contains 160 liters of water,
And the tank lost 20 liters by leakage,
So the percent of water lost is
20/160 × 100
on solving, we will get 12.5%.
The percent of water lost is 12.5%
5. The total number of students in grade 8 is 70 and in that 63 students are qualified for grade 9. What will be the qualified percent of the grade 8th students?
Solution:
The total number of students in grade 8 are 70 students,
And in that 63 students are qualified to grade 9,
The qualified percent of grade 9 is
63/70 × 100
on solving we will get the result as
90%.
So 90% of students are qualified to grade 9.
6. Mary has $50 with her and she bought groceries worth of $20. Express this in percent?
Solution:
As Mary has $50 and she bought $20 worth of groceries,
So the percent is
20/50 ×100=
on solving, we will get
40%.